Logic puzzles can be an actual work of art. It just takes a few simple elements put together in the right way to create a brainteaser that will entertain friends and families for hours. Not only do they test your wits, but they also make you think about things in a completely different way. And the best thing about mind puzzles is that you don’t need to be a smartass to solve them. Putting your brain to work is enough! You may need to use clues given in the questions and really focus on what these brain puzzles are asking you to do.
Today we want to challenge you with some of the most fantastic logic riddles we found scattered on the internet, including some that will really challenge your brain and force you to think outside the box. The answers to these logic problems often aren’t easy to come up with, but if you use your brain properly, there’s a good chance you’ll figure them out before too long! So let’s get started!
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A man is caught on the king's property. He is brought before the king to be punished. The king says, "You must give me a statement. If it is true, you will be killed by lions. If it is false, you will be stomped by trampling of wild buffalo. If I can’t figure it out, I’ll have to let you go.” Sure enough, the man was released. What was the man's statement?
OR stuff like “this statement is false” since if it were true then it would be false and now my brain hurts
Answer: "I will be stomped by trampling of wild buffalo.” This stumped the king because if it’s true, he’ll be killed by lions, which would render the statement not true. If it’s a lie, he’d be killed by wild buffalo, which would make it a truth. Since the king had no solution, he had to let the man go.
Just say, "If I'm having blue, then wasn't us not trumpet banana". It's neither true or false, and the king wouldn't know what it means.
Two fathers took their sons fishing. Each man and son caught one fish, but when they returned to camp there were only 3 fish. How could this be? (None of the fish were eaten, lost, or thrown back)
They're actually riddles, if you want to use the correct term.
Load More Replies...Father and son are taking an airplane trip. The son asked the air hostess whether he can see the cockpit (this was pre-9/11). She said she'd check with the pilot, and when she came back took him up to the flight deck. The boy was in aw over all the instruments, asked lots of questions, and after 15 minutes returned to his seat. The co-pilot said: "Nice kid; and smart!" The captain said: "Of course he is smart; he is my son!" - How can that be? (Answer: the captain was his mother.)
I think it would be better if it is said "two fathers and two sons went fishing" rather than the version given here. Otherwise in the present version if you stretch it a bit the answer could be a gay couple with their adopted son.
no, not really, the present version says sons, plural.
Load More Replies...Answer: There were only three people. The son, his father, and his grandfather.
A man took his son fishing, and the man's son took HIS son fishing
Load More Replies...You’re at a fork in the road in which one direction leads to the City of Lies (where everyone always lies) and the other to the City of Truth (where everyone always tells the truth). There’s a person at the fork who lives in one of the cities, but you’re not sure which one. What question could you ask the person to find out which road leads to the City of Truth?
Since you can ask the person as many questions as you want (nothing in the riddle states otherwise), I would simply ask "do I have blonde or brown hair?", and would know how to interpret all other answers.
But then you still don't know which road leads where
Load More Replies...Answer: “Which direction do you live?” Someone from the City of Lies will lie and point to the City of Truth; someone from the City of Truth would tell the truth and also point to the City of Truth.
There are two ducks in front of a duck, two ducks behind a duck and a duck in the middle. How many ducks are there?
Hmm . . . yeah I guess it should ask what's the minimum number of ducks present
Load More Replies...The math doesn't check out on this one. Edit: Figured it out! LOL Imagine three ducks walking in single file. Ducks #1, #2, and #3... "There are two ducks in front of a duck" - Ducks #1 & #2 are in front of #3. "Two ducks behind a duck" - Ducks #2 & #3 are behind duck #1 "And a duck in the middle" - Duck #2 is between #1 & #3
Lol i had the math didn't check out either at first. I originally thought of an X formation where 2 ducks would always be side to side one another meaning it couldn't have been both ways. Though 5 would've if there were 2 in front and 2 behind one in the middle. But yeah i agree that in a row 3 would work.
Load More Replies...Answer: Three. Two ducks are in front of the last duck; the first duck has two ducks behind; one duck is between the other two.
The answer is not three. It's any number that's is equal to or greater than three.
You can't assume that there are more than 3 ducks..the two ducks could at one point be behind the 1 duck and then walk in front of it..hence not two sets of 2 ducks 🤔
You are about to leave for holiday, but you forgot socks! You race back to your room, but the power is off so you can't see sock colors. Never mind, because you remember that in your drawer there are ten pairs of green socks, ten pairs of black socks, and eleven pairs of blue socks, but they are all mixed up. How many of your socks do you need to take before you can be sure to have at least one matching pair?
Proper Answer: send this guy to a mental hospital, why aren't your socks paired up
A: you're going on holiday! Who gives a flying fart if your socks match??
I don't wear matching socks anyhow, so who the hell gives a damn.?
Load More Replies...These questions are usually solved by assuming the "worst case scenario" i.e. on first three attempts you draw one each of green, black or blue. On the fourth attempt no matter what colour you pick there is bound to be a pair.
Any number above three is a "correct" answer. The question should be phrased as "least number of socks ..." then "four" would be the answer.
Answer: Four. Although there are many socks in the drawer, there are only three colors, so if you take four socks then you are guaranteed to have at least one matching pair.
Proper Answer: send this guy to a.mental hospital, why aren't your socks paired up
A farmer wants to cross a river and take with him a wolf, a goat and a cabbage. He has a boat, but it can only fit himself plus either the wolf, the goat or the cabbage. If the wolf and the goat are alone on one shore, the wolf will eat the goat. If the goat and the cabbage are alone on the shore, the goat will eat the cabbage. How can the farmer bring the wolf, the goat and the cabbage across the river without anything being eaten?
Make cabbage soup. Take goat and soup across, and share soup with goat once you are both safely away from the wolf. Who wants to bring a g©£@#€d wolf with them, anyway? 😜😂
You need to get him out of the way because Red Riding Hood will be passing by soon.
Load More Replies...That's a lot of trips. I have a feeling the wolf would eat the farmer too.
1. Take the goat across. 2. Return alone. 3. Leave the wolf. Why did you have a wolf? https://xkcd.com/1134/
I was going to say have the goat eat the cabbage then have the wolf eat the goat. All three are on board and only one trip.
Answer: First, the farmer takes the goat across. The farmer returns alone and then takes the wolf across, but returns with the goat. Then the farmer takes the cabbage across, leaving it with the wolf and returning alone to get the goat.
There are only two barbers in town. One of them has a nice, neatly trimmed head of hair. The other one's hair is a complete mess. Which of the two barbers should you go to and why?
I'm tired of this kind of "logic". What if the first barber is such a great stylist that he can cut his own hair well and the messy one is too proud to go to the first and so tries to give himself a trim and is in denial about how jacked up he looks?
You have two ropes that each take an hour to burn, but burn at inconsistent rates. How can you measure 45 minutes? (You can light one or both ropes at one or both ends at the same time.)
Same. I'd actually rather use a damn sundial than this (not a good) trick.
Load More Replies..."You can light one or both ropes at one or both ends at the same time." This means that you cannot, in fact, light the second rope at a different time. If you fold one rope in half, then half again, you can burn at the short bend (3/4 of the way through). It might not be exactly 45 minutes (inconsistent burn times) but it will be as close as the answer given without breaking the rules (since the bend could be considered an end)
But if they burn at inconsistent rates, then one side could burn faster/slower than the other side?
Nah, it works out even so, cos the side that burns faster keeps on burning into the slower side
Load More Replies...Answer: Because they both burn inconsistently, you can’t just light one end of a rope and wait until it’s 75 percent of the way through. But, this is what you can do: Light the first rope at both ends, and light the other rope at one end, all at the same time. The first rope will take 30 minutes to burn (even if one side burns faster than the other, it still takes 30 minutes). The moment the first rope goes out, light the other end of the second rope. Because the time elapsed of the second rope burning was 30 minutes, the remaining rope will also take 30 minutes; lighting it from both ends will cut that in half to 15 minutes, giving you 45 minutes all together.
Find someone with a watch and say "If you tell me when 45minutes are up, I'll give you these nice ropes."
There is a lightbulb inside a closet. The door is closed, and you cannot see if the light is on or off through the door. However, you know the light is off to start. Outside of the closet, there are three light switches. One of the switches controls the lightbulb in the closet. You can flip the switches however you want, but once you open the door, you can no longer touch the switches. How do you figure out without a doubt which switch controls the light?
What if it's an LED bulb that doesn't get hot, or there's a short in the wiring?
This riddle was written a long time before LED bulbs were created.
Load More Replies...Answer: Flip switch number 1 and wait a few minutes. Flip switch number 1 back to its original position, and then immediately flip switch number 2. Open the door. If the light is on, then switch number 2 controls it. If the light is off, then go and feel the bulb with your hand. If the bulb is hot, the switch number 1 controls it, and if the bulb is cold, then switch number 3, the one you did not touch, controls it.
Y'all did not complain this much about the farmer with his wolf/goat/cabbage dilemma.
What if the power went off while we were trying this world saving experiment?
Look around the door edges. Through the keyhole. Open the door, put a chock under the door to hold it open, then flick the switches on.
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Abigail, Oliver, Rosa, and Blake all attend the same summer camp, where they can cook, kayak, rock climb, and zip-line. Each child has a different favorite activity. Abigail’s favorite activity isn’t rock climbing. Oliver is afraid of heights. Rosa can’t do her favorite activity without a harness. Blake likes to keep his feet on the ground at all times. Can you figure out who likes what?
Simple logic puzzle. Love these. It's easier to solve them we with the chart.
Answer: Abigail likes to zip-line, Oliver likes to kayak, Rosa likes to rock climb, and Blake likes to cook.
I have to disagree about the two girls. You can rock climb without a harness, but you can’t zip-line without such.
But if Oliver is afraid of hieghts then he is above water while kayaking
I wouldn't call sitting in a kayak on water keeping your feet on the ground
Didn't read that right did ya? Blake is the no feet on the ground and he cooks. The kayak is Oliver. Oliver doesn't like heights.
Load More Replies...Answer makes no sense. Rosa -> rock climb Oliver -> cook or kayak Blake -> cook or kayak (feet on the ground can still be valid for kayaking as he is not in the air) Abigail -> cook, kayak, or zip line
Only one child can do each activity,..basic rules of logic puzzles. So once it's determined that, say, Oliver kayaks, no one else can. Even if you interpret Blake's "keeping his feet on the ground as he could kayak (and sitting in a kayak definitely takes your feet off the ground), he couldn't kayak because Oliver does. Then Abigail can't do either of those, so she zip-lines, and Rosa rock-climbs.
Load More Replies...There is a barrel with no lid and some wine in it. “This barrel of wine is more than half full,” says the woman. “No, it's not,” says the man. “It’s less than half full.” Without any measuring implements and without removing any wine from the barrel, how can they easily determine who is correct?
The son recently had a house party and they know it was less than half full before so they need to figure out if something was added
Load More Replies...Answer: Tilt the barrel until the wine barely touches the lip of the barrel. If the bottom of the barrel is visible then it is less than half full. If the barrel bottom is still completely covered by the wine, then it is more than half full.
That would depend on the shape of the barrel, no?
Load More Replies...Five friends (Allegra, Ben, Clara, Flora, and Zach) are each allergic to something different: pollen, shellfish, bee stings, cats, or nuts. Allegra has a food allergy. Ben can play with his kitten for hours without issue (or medicine). Clara’s allergy is not related to animals. Flora has seasonal allergies. Can you figure out who is allergic to what?
Bees don't sting in winter, therefore pollen and been stings are both seasonal and Ben and Flora are interchangeable.
I guess you don't live in the bottom quarter of America. Normally, there are no real season changes, just slightly cooler temps.
Load More Replies...Answer: Allegra is allergic to shellfish, Ben to bee stings, Clara to nuts, Flora to pollen, and Zach to cats.
Four playing cards, one of each suit, lie face down on a table. They are a three, a four, a five, and a six. The cards on either side of the four are black. The club is to the right of the three but not next to it. The spade is to the left of the heart. The middle two cards add up to an even number. Neither of them is a club. Can you determine the cards’ suits and their order?
Since the cards on either side of the 4 are black they must either be in positions 1 and 3 or 2 and 4. Neither middle card is a club, which means that the club is either at 1 or 4. But it can't be at 1 since it must be to the right of the 3. So the club is at 4 and the spade is at 2. The spade is to the left of the heart, putting the heart at position 3. The order of the suits is therefore diamonds, spade, heart, club. The two middle cards must add up to an even number, making them both even or both odd making them either 3 and 5 or 4 and 6. Since the black cards are on either side of the 4 the four must be in position 3, which means that 6 has to occupy position 2. The club is to the right of the 3 but not next to it, so the 3 must be at position 1. So the solution: 3 Diamond, 6 Spades, 4 Hearts, 5 Clubs
Answer: From left to right: Three of diamonds, six of spades, four of hearts, five of clubs.
The answer given is wrong. It says the cards on either side of the four are black. So the first one would be black. It gives the first one as diamonds.
The first or second could be black. The cards on either side of the four being black only requires the first and the third card to be black, or the second and fourthl The solution is correct. See my post for an explanation.
Load More Replies...Without the last clue you couldn't determine the possible positions of the clubs at either end.
Load More Replies...Did the recent Nobel laureate in applied mathematics submit this one?? Damn, y'all...
The day before two days after the day before tomorrow is Saturday. What day is it today?
Its Saturday. The answer ignores 1 day in the question. Day before +1 Sunday 2 Days After -2 Friday The day before +1 Saturday
Answer: Friday. The “day before tomorrow” is today; “the day before two days after” is really one day after. So if “one day after today is Saturday,” then it must be Friday.
"Damn it, Fred, I just need the date to sign this check. Stop making everything so damned complicated!"
Godzilla has a stroke trying to understand this and f-ing died
That's what I was thinking. I don't get this logic
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Four people are crossing a bridge at night, so they all need a torch—but they just have one that only lasts 15 minutes. Alice can cross in one minute, Ben in two minutes, Cindy in five minutes and Don in eight minutes. No more than two people can cross at a time; and when two cross, they have to go at the slower person’s pace. How do they get across in 15 minutes?
Answer: Alice and Ben cross first in two minutes, and Alice crosses back alone with the torch in one minute. Then the two slowest people, Cindy and Don, cross in eight minutes. Ben returns in two minutes, and Alice and Ben return in two minutes. They just made it in 15 minutes exactly.
If five cats can catch five mice in five minutes, how long will it take one cat to catch one mouse?
This is one of those ones where I figured it out in 20 seconds because it felt obvious, but then got confused by explaination- which seems to take the longest way around - then became inundated with self doubt (even though I had the same answer) and now I'm pretty sure we're all wrong, and it's 42 just to spite us.
That answer is taken. 42 is the answer to the meaning of life
Load More Replies...It pretty much says it in the first sentence. each cat is catching a mouse in five minutes therefore one cat takes 5 minutes to catch one mouse.
No more than 5 minutes is only thing that could be said for sure. In 1st case we can learn only that even the slowest cat have managed to make a catch in 5 minutes.
Answer: Five minutes. Using the information we know, it would take one cat 25 minutes to catch all five mice (5x5=25). Then working backward and dividing 25 by five, we get five minutes for one cat to catch each mouse.
A girl meets a lion and unicorn in the forest. The lion lies every Monday, Tuesday and Wednesday and the other days he speaks the truth. The unicorn lies on Thursdays, Fridays and Saturdays, and the other days of the week he speaks the truth. “Yesterday I was lying,” the lion told the girl. “So was I,” said the unicorn. What day is it?
Answer: Thursday. The only day they both tell the truth is Sunday; but today can’t be Sunday because the lion also tells the truth on Saturday (yesterday). Going day by day, the only day one of them is lying and one of them is telling the truth with those two statements is Thursday.
Why would a girl talk to a lion… just curious, I know its not real but can it understand
Jack is looking at Anne. Anne is looking at George. Jack is married, George is not, and we don’t know if Anne is married. Is a married person looking at an unmarried person?
If Anne is married, she's looking at George, who isn't. If Anne isn't married, she's being looked at by jack, who is. Either way, a married person is looking at an unmarried person
Load More Replies...Answer: Yes. If Anne is married, then she is married and looking at George, who is unmarried. If Anne is unmarried, then Jack, who is married, is looking at her. Either way, the statement is correct.
Each of five neighborhood dogs (Saber, Ginger, Nutmeg, Pepper, and Bear) is enjoying one of the following activities: getting its ears scratched, playing catch, taking a nap, burying a chew toy, and going for a walk. Pepper is either playing catch or burying a chew toy. Neither Ginger nor Saber nor Bear is on a walk. One of the dogs named after a spice is getting its ears scratched. A dog not named for a spice is playing catch. Bear is getting some exercise. Can you figure out what each pooch is doing?
Answer: Saber is taking a nap, Ginger is getting her ears scratched, Nutmeg is going for a walk, Pepper is burying a chew toy, and Bear is playing catch.
The answer is not correct. Bear can’t be the one playing catch, because it is stated that the one playing catch it’s a dog named for a spice. I think bear is walking and nutmeg is the one playing catch.
It says "a dog NOT named for a spice is playing catch"
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A person bought an item for $7, sold it for $8, bought it back for $9, and sold it for $10. How much profit did he make?
He bought it Back... He made 1$ profit in first selling but as he BOUGHT IT BACK , bought 8$ thing in 9$ he actually lost that 1$ and then made Profit of 1$ Again. Total profit is only 1$. But can be 2$ too in some way
Think of it as two separate sales. First sale he made a dollar, second sale he made a dollar. It's irrelevant that he bought back his own item. Just imagine he bought item A the first time and item B the second time.
Load More Replies...Say she has $10. Spends $7 buying, $10-$7=$3. Makes $8 selling, $3+$8=$11. Spends $9 buying, $11-$9=$2. Makes $10 selling, $2+$10=$12. Started with $10, ended with $12, $12-$10=$2. She made $2 in profit.
Think about it like this. He buys a shirt for 7 and sells for 8. Then, he buys another shirt for 9 and sells for 10. It wouldn't matter if it's the same shirt or not.
Assume person A starts with $10. Spends $7, now holds $3. Sells to get $8+3 holding $11. Spend $9 leaving $2 in hand. Sells for $10+2 in hand = $12. Since started with $10, made $2.
I'm no mathematician, but if he had 7 to start and ended with 10, I'm pretty sure he made $3
Six neighborhood children (Leisha, Benito, Delia, Charlotte, Weldon, and Zina) were measured yesterday. Weldon is taller than Delia but shorter than Zina. Leisha is taller than Benito but shorter than Delia and Weldon. Benito is not the shortest. Can you put them in order of height from tallest to shortest?
There are five gears connected in a row, the first one is connected to the second one, the second one is connected to the third one, and so on. If the first gear is rotating clockwise what direction is the fifth gear turning?
Three men are lined up behind each other. The tallest man is in the back and can see the heads of the two in front of him; the middle man can see the one man in front of him; the man in front can’t see anyone. They are blindfolded and hats are placed on their heads, picked from three black hats and two white hats. The extra two hats are hidden and the blindfolds removed. The tallest man is asked if he knows what color hat he’s wearing; he doesn’t. The middle man is asked if he knows; he doesn’t. But the man in front, who can’t see anyone, says he knows. How does he know, and what color hat is he wearing?
Must assume the men know how many hats of each color they started with. Going from back to front: If the back man sees two white hats, he knows he is wearing a black hat, because there were only two white hats total. If the back man sees anything other than two white hats in front of him, he doesn't know what color he has. So the other two men know he didn't see two white hats on the two other men. If the middle man sees a white hat on the front man, he will know that he, the middle man, is wearing a black hat. Since the middle man can't say he knows what color hat he himself is wearing, the front man knows that he himself is not wearing a white hat. Thus, the front man is wearing a black hat.
Answer: Black. The man in front knew he and the middle man aren’t both wearing white hats or the man in the back would have known he had a black hat (since there are only two white hats). The man in front also knows the middle man didn’t see him with a white hat because if he did, based on the tallest man’s answer, the middle man would have known he himself was wearing a black hat. So, the man in front knows his hat must be black.
Daniel, Emily, Marciano, and Christina are all wearing solid-colored shirts. Their shirts are red, yellow, green, and blue. Only the person wearing blue tells the truth, while the other three lie. They make the following statements: Daniel: “Marciano is wearing red.” Emily: “Daniel is not wearing yellow.” Marciano: “Emily is wearing blue.” Christina: “I will wear blue tomorrow.” Can you determine each person’s shirt color, and whether we can expect to see Christina in blue tomorrow?
Answer: Daniel is wearing yellow, Emily is in red, Marciano is in green, and Christina is in blue. Christina will wear a blue shirt again tomorrow.
A bad guy is playing Russian roulette with a six-shooter revolver. He puts in one bullet, spins the chambers and fires at you, but no bullet comes out. He gives you the choice of whether or not he should spin the chambers again before firing a second time. Should he spin again?
Imagine: he spins and it stops at exact at hole filled with bullet 💀
Answer: Yes. Before he spins, there’s a one in six chance of a bullet being fired. After he spins, one of those chances has been taken away, leaving a one in five chance and making it more likely a bullet will be fired. Best to spin again.
Not wanting to be nit picking here, but the *real* Russian Roulette was played with an old Russian army service revolver which only had THREE chambers. Made the game for fun, I guess...
Should read, "After he fires, one of those chances has been taken away....... "
A joint Father’s Day and graduation party is being thrown for Michael, Ken, James, Alberto, Elias, and Stephanie. Three of them are newly minted high school graduates. The other three are their dads. Stephanie went to the senior prom with Michael’s son. Elias and James played on the school’s baseball team. One of them is Alberto’s son. Michael and Elias are not related. Can you match the high school graduates to their fathers at this joint celebration?
Answer: Alberto is Elias’ dad, Ken is Stephanie’s dad, and Michael is James’ dad.
Five people were eating apples, A finished before B, but behind C. D finished before E, but behind B. What was the finishing order?
Answer: CABDE. Putting the first three in order, A finished in front of B but behind C, so CAB. Then, we know D finished before B, so CABD. We know E finished after D, so CABDE.
Susan and Lisa decided to play tennis against each other. They bet $1 on each game they played. Susan won three bets and Lisa won $5. How many games did they play?
Answer: Eleven. Because Lisa lost three games to Susan, she had lost $3 ($1 per game). So, she had to win back that $3 with three more games, then win another five games to win $5.
There are three crates, one with apples, one with oranges, and one with both apples and oranges mixed. Each crate is closed and labeled with one of three labels: Apples, Oranges, or Apples and Oranges. The label maker broke and labeled all of the crates incorrectly. How could you pick just one fruit from one crate to figure out what’s in each crate?
Answer: Pick a fruit from the crate marked Apples and Oranges. If that fruit is an apple, you know that the crate should be labeled Apples because all of the labels are incorrect as they are. Therefore, you know the crate marked Apples must be Oranges (if it were labeled Apples and Oranges, the Oranges crate would be labeled correctly, and we know it isn’t), and the one marked Oranges is Apples and Oranges. Alternately, if you picked an orange from the crate marked Apples and Oranges, you know that crate should be marked Oranges, the one marked Oranges must be Apples, and the one marked Apples must be Apples and Oranges.
A teacher writes six words on a board: “cat dog has max dim tag.” She gives three students, Albert, Bernard and Cheryl each a piece of paper with one letter from one of the words. Then she asks, “Albert, do you know the word?” Albert immediately replies yes. She asks, “Bernard, do you know the word?” He thinks for a moment and replies yes. Then she asks Cheryl the same question. She thinks and then replies yes. What is the word?
I looked it up. The teacher must tell them that they each have one letter from a chosen word on the list. Which word is it? They must know that the mystery word is on the list, that their letter is from that word and that they each have a different letter.
Answer: Dog. Albert knows right away because he has one of the unique letters that only appear once in all the words: c o h s x i. So, we know the word is not “tag.” All of these unique letters appear in different words, except for “h” and “s” in “has,” and Bernard can figure out what the word is from the unique letters that are left: t, g, h, s. This eliminates “max” and “dim.” Cheryl can then narrow it down the same way. Because there is only one unique letter left, the letter “d,” the word must be “dog.”
I think something is missing in this riddle. “Do you know the word?” There are no limits/description/definition of what or where this word comes from. Why not dead, fish, man, experience, or any other word?
Ruby and Lewis are expecting… Triplets! They already know what they will name their three children, but they aren’t sharing the names until the babies are born. For now, this is all they’ll say: · All three babies are boys. · Their names are six letters long and anagrams of one another. · Their names include both of their parents’ initials, but none of the other letters in their parents’ first names. What will Ruby and Lewis name their triplets?
A man has 53 socks in his drawer: 21 identical blue, 15 identical black and 17 identical red. The lights are out and he is completely in the dark. How many socks must he take out to make 100 percent certain he has at least one pair of black socks?
These fools need better sock drawer habits and better electricity, maybe a backup generator or some solar panels and batteries, or at least a flashlight or a mobile phone with a flash on it. Oil lamps or something. I used to love it as a kid when the power would go out and we'd break out the oil lamps and candles.
When I met my late husband, he had probably two dozen or so white socks, but lots of different types (crew, tube, with a stripe, with a gray heel, etc). One of the happiest days of my marriage was when I bought four packs of the exact same white socks and threw out all his old ones.
Load More Replies...Answer: 40 socks. If he takes out 38 socks (adding the two biggest amounts, 21 and 17), although it is very unlikely, it is possible they could all be blue and red. To make 100 percent certain that he also has a pair of black socks he must take out a further two socks.
You have five boxes in a row numbered 1 to 5, in which a cat is hiding. Every night he jumps to an adjacent box, and every morning you have one chance to open a box to find him. How do you win this game of hide and seek?
Answer: Check boxes 2, 3, and 4 in order until you find him. Here’s why: He’s either in an odd or even-numbered box. If he’s in an even box (box 2 or 4) and you check box 2 and here’s there, great; if not you know he was in box 4, which means the next night he will move to box 3 or 5. The next morning, check box 3; if he’s not there that means he was in box 5 and so the next night he’ll be in box 4, and you’ve got him. If he was in an odd-numbered box to begin with (1, 3, or 5), though, you might not find him in that first round of checking boxes 2, 3 and 4. But if this is the case, you know that on the fourth night he’ll have to be in an even-numbered box (because he switches every night: odd, even, odd, even), so then you can start the process again as described above. This means if you check boxes 2, 3, and 4 in that order, you will find him within two rounds (one round of 2, 3, 4; followed by another round of 2, 3, 4).
The Reds, the Grays, the Blues, and the Blacks have a round-robin tournament. Each team plays each other team once, for a total of six games. The Blacks won more games than the Blues. The Grays lost more games than the Blues. The Reds tied the Blacks (this was the only tie in the tournament). Who won the game between the Reds and the Blues?
At the Pet Show recently I noticed that all except two of the entries were cats, all except two were dogs, and all except two were fish. How many of each animal were at the Pet Show?
Answer: All except two were dogs and all except two were cats. So two animals were not dogs and two animals were not cats. One of the "not dogs" could have been a cat, and one of the "not cats" could have been a dog. Combine this with the fact that all except two of the pets were fish and we have the result: one dog, one cat, one fish - three animals at the Pet Show.
There are three people (Alex, Ben and Cody), one of whom is a knight, one a knave, and one a spy. The knight always tells the truth, the knave always lies, and the spy can either lie or tell the truth. Alex says: "Cody is a knave.” Ben says: "Alex is a knight.” Cody says: "I am the spy.” Who is the knight, who the knave, and who the spy?
Ya the answer was poor worded. We just know he's not a knight as that would make 2 knights.
Load More Replies...Answer: We know Ben isn’t telling the truth because if he was, there would be two knights; so Ben could be either the knave or the spy. Cody also can’t be the knight, because then his statement would be a lie. So that must mean Alex is the knight. Ben, therefore, must be the spy, since the spy sometimes tells the truth; leaving Cody as the knave.
Let’s pretend we’re on the metric system and use kilograms instead of pounds to give us a starting base number of 100. Four people (Alex, Brook, Chris and Dusty) want to cross a river in a boat that can only carry 100kg. Alex weighs 90kg, Brook weighs 80kg, Chris weighs 60kg and Dusty weighs 40kg, and they have 20kg of supplies. How do they get across?
Answer: There may be a couple variations that will work, but here’s one way: Chris and Dusty row across (combined 100kg), Dusty returns. Alex rows over, and Chris returns. Chris and Dusty row across again, Dusty returns. Brook rows across with the supplies (combined 100kg), and Chris returns. Chris and Dusty row across again.
George, William, John, Abe, and Millard have their birthdays on consecutive days, all between Monday and Friday. George’s birthday is as many days before Millard’s and William’s is after Abe’s. John is two days older than Abe. Millard’s birthday is on Thursday. Can you figure out whose birthday is on each day?
Answer: John’s is on Monday, George’s on Tuesday, Abe’s on Wednesday, Millard’s on Thursday, and William’s on Friday.
Suppose there is this little town with a finite numer of people: · No two inhabitants have exactly the same number of hairs. · No inhabitant has exactly 409 hairs. · There are more inhabitants than there are hairs on the head of any inhabitant. So, what is the largest possible number of inhabitants in that little town?
what if ALL inhabitants have more than 409 hairs? then there could be a countably infinite number of inhabitants. little is not quantified.
There are three bags, each containing two marbles. Bag A contains two white marbles, Bag B contains two black marbles, and Bag C contains one white marble and one black marble. You pick a random bag and take out one marble, which is white. What is the probability that the remaining marble from the same bag is also white?
The answer for this example above is completely wrong. The probability that the remaining marble from the same bag is also White ? It is NOT 2 out of 3. The TRUE answer is 1 out of 2. IF your first pick was a white marble, you either picked from bag A or bag C. Bag B is off the table, since it never, ever contained a white marble. Therefore, since you picked a white marble first, it had to have come from either A or C. Now, you only have the remaining option of picking another white marble OR a black marble. Therefore, your odds are 1 out of 2, for picking another white marble, out of the same bag.
Answer: 2 out of 3. You know you don’t have Bag B. But because Bag A has two white marbles, you could have picked either marble; if you think of it as four marbles in total from Bags A and C, three white and one black, you’ll have a greater chance of picking another white marble.
False! 2 out of 3 is the chance of pulling a white marble, since there are a total of 3 marbles left. BUT there is only one marble left in the bag chosen. There are only two possible bags, since the bag with two black marbles is eliminated. So the answer is 1 out o 2 or 50%
Did anyone else feel like this was the same 3 or so riddles over and over again with different imagery?
Yes. I think this is a good example of just because its content doesn't make it good
Load More Replies...these are all ancient; I remember a few of them from grade school -- fifty years ago!
Did anyone else feel like this was the same 3 or so riddles over and over again with different imagery?
Yes. I think this is a good example of just because its content doesn't make it good
Load More Replies...these are all ancient; I remember a few of them from grade school -- fifty years ago!
